Question
A wheelchair ramp to a public building forms a 15 degree angle with ground and reaches a height of 2.3 metres above the ground.
A) fill in these values on the diagram to the right.
B) Label the length of the ramp, X . Then find its length ( to one decimal place)
A) fill in these values on the diagram to the right.
B) Label the length of the ramp, X . Then find its length ( to one decimal place)
Answers
Sharon
Sin(15)=2.3m/x
X=2.3m x 5 in (15)
Sin (15) is 0.258819045
X=2.3m *0.258819045
X=0.59528303 in
The length is 0.6 m
X=2.3m x 5 in (15)
Sin (15) is 0.258819045
X=2.3m *0.258819045
X=0.59528303 in
The length is 0.6 m