Question

Use Gaussian elimination to find the complete solution to the system of equations, or state that none exists.

x + y + z = 9
2x - 3y + 4z = 7
x - 4y + 3z = -2

A. {(-7z/5+34/5 ,2z/5 +11/5 , z)}

b. {(- 7z/5+34/5 , 2z/5- 11/5 , z)}

c . {( z/5+ 34/5 , 2z/5+11/5 , z)}

C?

Answer 1

oh ho, now Gauss Jordan. We are cooking with gas here

Answer 2

But there is a limit to what I am going to try to type

Answer 3

http://www.gregthatcher.com/Mathematics/GaussJordan.aspx

Answer 4

Okay but my answer is C is that wrong or right ?

Answer 5

strange answer choices, arbitrary z
hang on

Answer 6

I don't know how to use that calculator , I've tried

Answer 7

Okay tHANKS

Answer 8

0 , 29/7 , 34/7 it says
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx

Answer 9

Hmm okay thanks anyways , I'ma just move on and check my other one

Answer 10

put in

+1 +1 +1 +9
+3 -3 +4 +7
+1 -4 +3 -2

3 rows, 4 columns

Answer 11

Those answer choices are wrong

Answer 12

whoops, 2 not three in row 2 beginning

put in

+1 +1 +1 +9
+2 -3 +4 +7
+1 -4 +3 -2

Answer 13

Thanks you

Answer 14

34/5 11/5 undefined 0
can not solve for z, bottom row all zero
put arbitrary z in and see what happens

Answer 15

34/5 + 11/5 + z = 9 ?
z = 9 - 9 = 0

2 * 34/5 - 3 * 11/5 + 4z = 7
7 + 4 z = 7
z = 0

ah ha, B

-7 z/5 + 2 z/5 + z IS ZERO LOL
Talk about fooling the student !

Answer 16

Lmao thank you so much , your the best :)