Asked by Kimbo
What is the equation of the line that passes through all the points in the table?
x -4 -2 0 2
y 0 -4 -8 -12
A. y= -2x-8
B. y= -2x-4
C. y= -4x-8
D. y= -4x-4
PLEASE EXPLAIN PLZZ
x -4 -2 0 2
y 0 -4 -8 -12
A. y= -2x-8
B. y= -2x-4
C. y= -4x-8
D. y= -4x-4
PLEASE EXPLAIN PLZZ
Answers
Answered by
Jai
Take two points from the given. For instance the first two points (-4,0) and (-2,-4).
Get the slope using the formula,
m = (y2 - y1) / (x2 - x1)
where
(x1,y1) and (x2,y2) are points on the line.
Substituting,
m = (0 - (-4)) / (-4 - (-2))
m = (0 + 4) / (-4 + 2)
m = 4 / -2
m = -2
Finally substitute the slope and a point in slope-intercept form of equation:
y - y1 = m(x - x1)
y - 0 = -2(x - (-4))
y = -2(x + 4)
y = -2x - 8
hope this helps~ `u`
Get the slope using the formula,
m = (y2 - y1) / (x2 - x1)
where
(x1,y1) and (x2,y2) are points on the line.
Substituting,
m = (0 - (-4)) / (-4 - (-2))
m = (0 + 4) / (-4 + 2)
m = 4 / -2
m = -2
Finally substitute the slope and a point in slope-intercept form of equation:
y - y1 = m(x - x1)
y - 0 = -2(x - (-4))
y = -2(x + 4)
y = -2x - 8
hope this helps~ `u`
Answered by
Kimbo
THANK YOU SM JAI
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