Asked by hope
a hollow spherical iron shell floats just completely submerged in water.the outer diameter is 50 cm and the density of iron is 7.9cm cubed .find he inner diameter of the shell
Answers
Answered by
Damon
volume of iron = (4/3)pi (Rout^3-Rin^3)
mass of iron = (1 g/cm^3)(4/3) pi Rout^3
so
density of iron = Rout^3/(Rout^3-Rin^3)
mass of iron = (1 g/cm^3)(4/3) pi Rout^3
so
density of iron = Rout^3/(Rout^3-Rin^3)
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