Question

What is the change in entropy when 6.03 mL of liquid benzene (C6H6, d = 0.879 g/mL) is combusted in the presence of 26.8 L of oxygen gas, measured at 298 K and 1 atm pressure? (R = 0.0821 L · atm/(K · mol))
2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(l); ∆S° = –437.7 J/K at 298 K

Answer 1

dSrxn = (n*dSo products) - (n*dSo reactants)
Look the standard So values in tables in your text/notes/web.