Question

A man have 5 trucks. The capacity of trucks A and B are 2,5 ton, trucks C and D are 3 ton and the capacity of truck E is 1 ton more then the average capacities. Identify the capacity of truck E.

Answer 1

Let n = average capacity
Let n + 1 = capacity of E

Therefore, their average is
(2 + 5 + 3 + 3 + (n + 1))/5 = n

Solving for n,
(14 + n)/5 = n
14 + n = 5n
n - 5n = -14
-4n = -14
n = -14/-4
n = 7/2
n = 3.5 ton
n+1 = 4.5 ton (capacity of E)

hope this helps~ `u`