Question
A large container, 114 cm deep is filled with water. If a small hole is punched in its side 93.0 cm from the top, at what initial speed will the water flow from the hole?
Answers
SAAAME
Mass of water that escapes per unit time
= m
Since the mass of water drops in height by an equivalent of h=1.14 m, we can equate change in energy = 0,
or
mgh-(1/2)mv^2=0
Solve for v
= m
Since the mass of water drops in height by an equivalent of h=1.14 m, we can equate change in energy = 0,
or
mgh-(1/2)mv^2=0
Solve for v
v=(2hg)^1/2
v=(2*93*980)^1/2
v=426.9cm=4.269m
v=(2*93*980)^1/2
v=426.9cm=4.269m