Ask a New Question

Asked by Allen

A 75-W, 120-V bulb is connected in parallel with 25-W, 120-V bulb. What is the net resistance?
10 years ago

Answers

Answered by MathMate
Power = V²/r watts
so resistance for the 75W bulb
R1 = 120²/75 Ω = 192 Ω

Similarly calculate R2 for the 25W bulb.

Net resistance of two resistors in parallel
R = 1/(1/R1+1/R2)
10 years ago

Related Questions

What happens to a bulb when a conductor is wired in series with the bulb (bulb lights or dosen't lig... a 2 l gas bulb contains 4.07*10^23 N2 molecules. If the pressure is 3.05bar, what is the rms speed o... a gas bulb is connected to an open end manometer. the pressure in the bulb is .355 torr MORE than at... A 60W light bulb is connected to a 120V outlet. How long in seconds does it take for 1 billion (109)... A 346 W bulb and a 173 W bulb are both designed to operate at standard household voltage of 120 V.... Bulb A is 100 mL and contains Helium at 1 atm. Bulb B is 500 mL and contains Argon at 2 atm. The bul... If a bulb of 5ohms is connected across a 12V battery, what is the current flow through the bulb? The... You have an LED bulb that uses 4 watts of power and gives an output of 170 lumens. The operating vol... A 30-W led bulb and a 90-W led bulb are wired in the parallel to a 120-V source. You plug in a third... A 150 W light bulb is connected to this power source and it glows at its maximum brightness. Use t...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use