Asked by Rick
a model rocket is projected straight upward from the ground level. It is fired with an initial velocity of 192 ft/s. How high is the rocket after 10 seconds? When is the rocket at a height of 432 feet? What is the maximum height of the rocket? When will the rocket hit the ground?
Answers
Answered by
Henry
b. h = Vo*t + 0.5g*t^2
Vo = 192 Ft/s
g = -32Ft/s^2
h = 432 Ft.
Solve for t(Use Quadratic formula).
c. h max = -(Vo^2)/2g = -(192^2)/-64 =
576 Ft.
d. V = Vo + g*Tr = 0
Tr = -Vo/g = -192/-32 = 6 s. = Rise time
Tf = Tr = 6 s. = Fall time.
Tr+Tf = 6 + 6 = 12 s. to hit gnd.
Vo = 192 Ft/s
g = -32Ft/s^2
h = 432 Ft.
Solve for t(Use Quadratic formula).
c. h max = -(Vo^2)/2g = -(192^2)/-64 =
576 Ft.
d. V = Vo + g*Tr = 0
Tr = -Vo/g = -192/-32 = 6 s. = Rise time
Tf = Tr = 6 s. = Fall time.
Tr+Tf = 6 + 6 = 12 s. to hit gnd.
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