39. (Taken from problem 5 at the end of Chapter 9) Look at the children balanced on the see-saw in the figure below. r1 = 1.60 m. The center mass of the seesaw is located 0.16 m to the left of the pivot point. The seesaw board has a mass of 12.0 kg which produces a weight of (12.0 kg ) (9.80 m/s2) = W3. The lighter child has a mass of 26.0 kg (m1) and the heavier child has a mass of 32.0 kg (m2).
a) Find r2, the distance the larger child must be sitting from the fulcrum point in order for the see-saw to balance. (10 Points) Answer: 1.36 m
b) Compute Fp, the load on the pivot. (10 Points) Answer: 686 N
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c) Compute the force exerted by the heavier child on the seesaw. (10 Points) Answer: 976 N
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