Asked by Carmen

if 0.600 moles of copper(II) sulfide is treated with 1.40 moles of nitric acid, how many moles of copper(II) nitrate could be produced?

Answers

Answered by Steve
CuS + 2HNO<sub>3</sub> = Cu(NO<sub>3</sub>)<sub>2</sub> + H<sub>2</sub>S

That should help, right?
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