Asked by Carmen
if 0.600 moles of copper(II) sulfide is treated with 1.40 moles of nitric acid, how many moles of copper(II) nitrate could be produced?
Answers
Answered by
Steve
CuS + 2HNO<sub>3</sub> = Cu(NO<sub>3</sub>)<sub>2</sub> + H<sub>2</sub>S
That should help, right?
That should help, right?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.