Asked by Carmen
                if 0.600 moles of copper(II) sulfide is treated with 1.40 moles of nitric acid, how many moles of copper(II) nitrate could be produced? 
            
            
        Answers
                    Answered by
            Steve
            
    CuS + 2HNO<sub>3</sub> = Cu(NO<sub>3</sub>)<sub>2</sub> + H<sub>2</sub>S
That should help, right?
    
That should help, right?
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