Asked by melissa

the perimeter of a rectangle is 35.54 inches longer than the perimeter of a square of side 6.75 inches. Find the perimeter of the rectangle to the nearest tenth of an inch.

Answers

Answered by Jai
Perimeter of square:
P = 4s
where s = side length.
Solve for P of square:
P = 4 * 6.75
P = 27

It was said that the P of rectangle is 35.54 inches longer than P of square. Thus,
P (rectangle) = 27 + 35.54
P (rectangle) = 62.54
round off to nearest tenth:
= 62.5 in
Answered by Edward
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Answered by Hello
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Answered by Bob
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Answered by Yui Hashiro
>_< aight bruh
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