Asked by happy
A tank has two pipes entering it.when operating together,they fill the tank in 40 minutes.operating independently,one of the pipes fills the tank 60 minutes faster than the other one does. calculate the time taken by each pipe to fill the tank on its own.
Answers
Answered by
Henry
Tank #1 = T min.
Tank #2 = (T+60) min.
T*(T+60)/(T+T+60) = 40 min
(T^2+60T)/(2T+60) = 40
T^2+60T = 80T+2400
T^2 - 20T - 2400 = 0
Use Quadratic Formula.
T = 60 min.
T + 60 = 60 + 60 = 120 min.
Tank #2 = (T+60) min.
T*(T+60)/(T+T+60) = 40 min
(T^2+60T)/(2T+60) = 40
T^2+60T = 80T+2400
T^2 - 20T - 2400 = 0
Use Quadratic Formula.
T = 60 min.
T + 60 = 60 + 60 = 120 min.
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