Asked by Anonymous
Determine the coefficient of
w x^3 y^2 z^2 in (2w−x+y−2z)^8.
Thanks.
w x^3 y^2 z^2 in (2w−x+y−2z)^8.
Thanks.
Answers
Answered by
Steve
(2w+a)^8 = ... + 16wa^7 + ...
(-x+b)^7 = ... - 35x^3b^4
(y-2z)^4 = ... + 24y^2z^2
So, I get -13440wx^3y^2z^2
(-x+b)^7 = ... - 35x^3b^4
(y-2z)^4 = ... + 24y^2z^2
So, I get -13440wx^3y^2z^2
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