Asked by Lucina
Convert from standard to vertex form:
(x+5)(x+4)
x^2+ 9x + 20
(x+3)^2 + 20 - 9
(x+3)^2 + 11 <------
(x+5)(x+4)
x^2+ 9x + 20
(x+3)^2 + 20 - 9
(x+3)^2 + 11 <------
Answers
Answered by
Steve
not quite. since (x+a)^2 = x^2+<u>2ax</u>+a^2,
x^2+9x = x^2+9x+(9/2)^2-(9/2)^2
x^2+9x+20
= (x + 9/2)^2 + 20-81/4
= (x + 9/2)^2 + 319/4
x^2+9x = x^2+9x+(9/2)^2-(9/2)^2
x^2+9x+20
= (x + 9/2)^2 + 20-81/4
= (x + 9/2)^2 + 319/4
Answered by
Lucina
One question:
Shouldn't the answer be (x + 9/2)^2 -1/4 ?
Because 20 - (81/4) = -0.25
Shouldn't the answer be (x + 9/2)^2 -1/4 ?
Because 20 - (81/4) = -0.25
Answered by
Reiny
I agree with you
x^2+9x+20
= x^2 + 9x + 81/4 - 81/4 + 20
= (x+9/2) + 20 - 81/4
= (x+9/2)^ - 1/4
x^2+9x+20
= x^2 + 9x + 81/4 - 81/4 + 20
= (x+9/2) + 20 - 81/4
= (x+9/2)^ - 1/4
Answered by
Lucina
Thank you!
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