Asked by Anonymous

Let f(x)=2x+15−19ex. Then the equation of the tangent line to the graph of f(x) at the point (0,−4) is given by y=mx+b for

m=?
b=?
Answered by Steve
f = 2x+15-19e^x
f' = 2-19e^x
f'(0) = 2-19 = -17

so, the tangent line is

y+4 = -17(x-0)

see the graphs at

http://www.wolframalpha.com/input/?i=plot+y%3D2x%2B15-19e%5Ex%2C+y%3D-17x-4
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