Question
Let f(x)=2x+15−19ex. Then the equation of the tangent line to the graph of f(x) at the point (0,−4) is given by y=mx+b for
m=?
b=?
m=?
b=?
Answers
Steve
f = 2x+15-19e^x
f' = 2-19e^x
f'(0) = 2-19 = -17
so, the tangent line is
y+4 = -17(x-0)
see the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D2x%2B15-19e%5Ex%2C+y%3D-17x-4
f' = 2-19e^x
f'(0) = 2-19 = -17
so, the tangent line is
y+4 = -17(x-0)
see the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D2x%2B15-19e%5Ex%2C+y%3D-17x-4