Asked by Dani
Let f(x)=(lnx)^4
f'(x)=4(ln(x))^3/x
what is f'(e^2)=?
f'(x)=4(ln(x))^3/x
what is f'(e^2)=?
Answers
Answered by
Steve
well, geez, just plug in e^2 into f'(x)
f'(e^2) = 4(ln(e^2))^3/e^2
= 4(2)^3/e^2
= 32/e^2
remember
ln(e^u) = u
e^(ln u) = u
f'(e^2) = 4(ln(e^2))^3/e^2
= 4(2)^3/e^2
= 32/e^2
remember
ln(e^u) = u
e^(ln u) = u
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