Asked by Maggie
Find a special factoring pattern for a difference of two sextics: (a^6-b^6).
Answers
Answered by
Reiny
first step:
(a^3 - b^3)(a^3 + b^3)
second step: we can factor the sum and difference of cubes, should be in your notes or text
= (a-b)(a^2 + ab + b^2)(a+b)(a^2 - ab + b^2)
(a^3 - b^3)(a^3 + b^3)
second step: we can factor the sum and difference of cubes, should be in your notes or text
= (a-b)(a^2 + ab + b^2)(a+b)(a^2 - ab + b^2)
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