Question

There are 9 red gum balls, 5 green gum balls, 8 yellow gum balls, and 8 blue gum balls in a machine. Find P(green, then yellow)

Answer 1

The answer is 40/870.

Answer 2

P(Green) = 5/30 = 1/6
P(yellow after green) = 8/29 (as one has been taken away)

Probability of both of these happening - so green and yellow afterwards is multiply the two probabilities together together

(1/6)*(8/29) = 8/174
Which is the same as Tia said if simplified

Answer 3

Prob(green, then yellow)
= (5/30)(8/29)
= 4/87

Answer 4

Oh yeah, I forgot I could simplify too. Thanks Reiny!