Question
What mass of manganese(II) chloride must react with sulfuric acid to release 54.0mL of hydrogen chloride gas at STP?
MnCl2(s)+H2SO4(aq)¨MnSO4(aq)+2HCl(g)
MnCl2(s)+H2SO4(aq)¨MnSO4(aq)+2HCl(g)
Answers
MathMate
From the equation, find the stoichiometric ratio of HCl and MnCl2 which equals 2.
This means that 1 mol of MnCl2 will generate 2 mol of HCl.
Using the fact that 1 mol of HCl occupies 22.4 L at STP, you will find how many mol of MnCl2 will be required to make 0.054 L of HCl.
This means that 1 mol of MnCl2 will generate 2 mol of HCl.
Using the fact that 1 mol of HCl occupies 22.4 L at STP, you will find how many mol of MnCl2 will be required to make 0.054 L of HCl.