Asked by ocre
Don't know where to begin.
1) A thermally activated process (a reaction) takes four minutes at 811°C. How long will it take (in minutes) at 748°C if the activation energy is 150 kJ/mol?
1) A thermally activated process (a reaction) takes four minutes at 811°C. How long will it take (in minutes) at 748°C if the activation energy is 150 kJ/mol?
Answers
Answered by
DrBob222
Use the Arrhenius equation. Choose any concentration you wish but the easy number is 1.
k1 is 1/4
k2 = ?
T2 is 811 C converted to K.
T1 is 748 C converted to K.
Ea is 150,000
Post your work if you get stuck.
k1 is 1/4
k2 = ?
T2 is 811 C converted to K.
T1 is 748 C converted to K.
Ea is 150,000
Post your work if you get stuck.
Answered by
ocre
but that get with this?????
Answered by
DrBob222
I don't understand. What does "but that get with this????" mean?
Answered by
ocre
yes, that formula I use for this
Answered by
DrBob222
It's the Arrhenius equation.
Substitute the numbers I gave in the earlier response and solve for k2.
Substitute the numbers I gave in the earlier response and solve for k2.
Answered by
ocre
the response must express it in minutes and I don't know where it will go out if what I get is a constant
I am grateful can collaborate me
I am grateful can collaborate me
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