f(x)=4x³
g(x)=2x
h(x)=x²
h◦(g◦f)
=h◦(g(x²))
=h◦(2(x²))
=h◦(2x²)
=4(2x²)³-5
=4(2²x²)³;-5
=4(2^6 x^6)-5
=256x^6-5
Given function f(x)=4x3-5, g(x)=2x and h(x)=x2. Find composition of h◦(g◦f)
3 answers
h◦(g◦f)
= h(g(f(x) ) )
= h(g(4x^3 - 5) ) )
= h(2(4x^3 - 5))
= ( 2(4x^3 - 5) )^2
manipulate this if needed.
testing with some value, say x = 2
according to my result:
(2(32-5))^2
= 2916
long way:
f(2) = 27
g(27) = 54
h(54) = 2916
= h(g(f(x) ) )
= h(g(4x^3 - 5) ) )
= h(2(4x^3 - 5))
= ( 2(4x^3 - 5) )^2
manipulate this if needed.
testing with some value, say x = 2
according to my result:
(2(32-5))^2
= 2916
long way:
f(2) = 27
g(27) = 54
h(54) = 2916
Oops, I didn't do what the question asked. Go with Reiny's solution!