While golfing, Sahar hits a tee shot from T toward a hole at H, but the ball veers 23 degrees and lands at B. The scorecard says that H is 270 m from T. If Sahar walks 160 m to the ball(B), how far, to the nearest metre, is the ball from the hole?

Answer 1

Did you make your sketch??

According to mine it is a simple case of the cosine law

HB^2 = 270^2 + 160^2 - 2(270)(160)cos 23°
= ..

take over