Asked by Bob

Sam and Jill had 576 stamps in all. Sam gave 1/7 of his stamps to Jill. Then Jill gave 1/4 of the total number of stamps she now had to Sam. In the end, both of them had the same number of stamps. What was the difference in the number of stamps they each had at first?
Answered by Henry
Sam has X stamps.
Jill has (576-X) Stamps.

X-x/7 = 6x/7 = Sam's bal.

576-x + x/7 = 576 - 6x/7 = Jill's bal.

1/4(576-6x/7) = 144 - 6x/28

3/4(576-6x/7) = 432 - 9x/14 = Jill's new
bal.

6x/7 + 144-6x/28 = 144 + 24x/28-6x/28 =
144 + 9x/14 = Sam's new bal.

Jill's new bal = Sam's new bal
432 - 9x/14 = 144 + 9x/14
18x/14 = 144-432 = 288
18x = 4032
X = 224
576-X = 576-224 = 352.
Difference = 352 - 224 128
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