37y^36 y' = 8x^7
y' = 8/37 x^7/y^36
Now, since y^37 = x^8,
y^36 = (x^8)^(36/37)
y' = 8/37 x^7 x^(-288/37)
= 8/37 x^(-29/37)
Doing it explicitly, using the power rule,
y = 8/37 x^(8/37 - 1) = 8/37 x^(-29/37)
Kind of a dumb problem to use to illustrate implicit differentiation.
Use implicit differentiation to differentiate y=x^(8/37), by writing it as y^37=x^8.
Express your answer only in terms of x.
1 answer