Question
a person in a wheelchair with a total mass of 100 kg is pushed from rest to a speed of 2.0m/s. if the effective coefficient of friction is .05 and the distance moved is 15 m calculate the work done, calculate the average force that must be exerted on the wheelchair to accomplish this
Answers
bobpursley
Vf^2=vi^2+2ad
but a= net force/mass=(pushing force-mg*.05)mass
a= force/mass -.05g
2^2=2*(force/100 - .05g)*15
solve for force.
but a= net force/mass=(pushing force-mg*.05)mass
a= force/mass -.05g
2^2=2*(force/100 - .05g)*15
solve for force.