Asked by Gem
In triangle PQR, we have <P = 30 degrees, <Q = 60 degrees, and <R=90 degrees. Point X is on line PR such that line QX bisects <PQR. If PQ = 12, then what is the area of triangle PQX$?
Answers
Answered by
Steve
since PQR = 60°, PQX = 30°
So triangle PQX is an isosceles triangle with base angles of 30° and base=12
Thus, its altitude is 6/√3 and its area = 36/√3 = 12√3
So triangle PQX is an isosceles triangle with base angles of 30° and base=12
Thus, its altitude is 6/√3 and its area = 36/√3 = 12√3
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