12000 was invested in two funds. the first made 5% interest and the second made 8%. the total interest earned was $768. How much wasinvested in each account.

Answer 1

amount invested at 5% ----x
amount invested at 8% -- 12000-x)

solve for x ....
.05x + .08(12000-x) = 768

I would suggest multiplying each term by 100 to get rid of those decimals

Answer 2

Invesed:
$X @ 5%.
$(12,000-X) @ 8%..
$768 = Tot. Int. earned.

0.05X + 0.08(12000-X) = 768
0.05x + 960 - 0.08x = 768
-0.03x = 768 - 960 = -192
X = $6400 @ 5%.
12,000 - X = 12000 - 6400 = $5600 @ 8%.