12) Two jeeps in the desert leave their starting points at noon. The first travels a course of 345º and averages 23 mph. The second travels a course of 45º and averages 20 mph. How far apart are the two jeeps at 10 PM? What is the bearing from the first jeep to the second at this time?

Answer 1

jeep A ends up at (-230 sin15º,230 cos15º) = (-59.53,222.16)
jeep B ends up at (200 sin45º,200cos45º) = (141.42,141.42)

So, the distance between them is

√((141.42+59.53)^2 + (141.42-222.16)^2) = 216.56

The angle from A to B is θ where
tanθ = (141.42-222.16)/(141.42+59.53) = -0.40

As a compass bearing, that would be 112º