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12 cards with letters in the word INDEPENDENCE are put into a bag. Two cards are randomly selected. The first card selected is not replaced. Find the probability that both card show vowels.

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I counted 5 vowels in the word,
Prob(both vowels) = (5/12)(4/11) =20/132

or
prob = C(5,2) / C(12,2) = 10/66 = 5/33

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