Let's use algebra to solve this problem.
Let x be the number of TV sets that weigh 30 kg, and y be the number of TV sets that weigh 50 kg.
From the problem, we know that:
- x + y = 20 (since there are 20 TV sets altogether)
- 30x + 50y = 880 (since the total weight of the shipment is 880 kg)
Now we have two equations with two unknowns, so we can solve for x and y.
One way to do this is to use the first equation to solve for one of the variables in terms of the other:
x + y = 20
x = 20 - y
Then we can substitute that expression for x into the second equation:
30x + 50y = 880
30(20 - y) + 50y = 880
600 - 30y + 50y = 880
20y = 280
y = 14
So there are 14 TV sets that weigh 50 kg. To find the number that weigh 30 kg, we can substitute y = 14 back into x + y = 20:
x + 14 = 20
x = 6
So there are 6 TV sets that weigh 30 kg.
Therefore, the answer is:
- 14 TV sets weigh 50 kg
- 6 TV sets weigh 30 kg
12. A shipment of TV sets, some weighing 30 kg each and the other weighing 50 kg each, has a total weight of 880 kg. If there are 20 TV sets all together, how many weigh 50 kg and how many weigh 30 kg?
1 answer