(11x-⁴)⁰/t-⁴u⁴

1 answer

The expression you provided is \( \frac{(11x^{-4})^0}{t^{-4}u^4} \).

Let's simplify it step by step:

  1. Evaluate the term with the exponent 0: Any non-zero expression raised to the power of 0 is equal to 1. Therefore, \( (11x^{-4})^0 = 1 \).

  2. Now simplify the fraction: \[ \frac{1}{t^{-4}u^4} \]

  3. Rewrite \( t^{-4} \): Recall that \( t^{-n} = \frac{1}{t^n} \), so \( t^{-4} = \frac{1}{t^4} \). Thus, \[ t^{-4} = \frac{1}{t^4} \implies \frac{1}{t^{-4}} = t^4 \]

  4. Combine the results: \[ \frac{1}{t^{-4}u^4} = \frac{1}{\frac{1}{t^4} u^4} = t^4 u^{-4} \]

So, the full simplified expression is:

\[ \frac{1}{t^{-4}u^4} = \frac{t^4}{u^4} \]

Hence, the final answer is:

\[ \frac{t^4}{u^4} \]

or alternatively expressed as:

\[ \frac{t^4}{u^4} = \frac{t^4}{u^4} = t^4 u^{-4} \]

If you need further assistance or have other questions, let me know!