Asked by vikas mahajan
PQRS IS A QUAD. IN WHICH DIAGONALS PR AND QS INTERSECT AT O.PROVE THAT PQ+QR+RS+SP>2(PR+QS).
Answers
Answered by
MathMate
Hint:
Use the triangular inequality,
a+b>c
where a,b,c represent three sides of any triangle.
Use the triangular inequality,
a+b>c
where a,b,c represent three sides of any triangle.
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