Asked by Anonymous
Integral of [1/(sqrt(8+2x-x^2))] dx
Answers
Answered by
Steve
you know that
∫ du/√(a^2-u^2) = arcsin(u/a)+C
right? So, just note that
8+2x-x^2 = 9-(x-1)^2
Now go for it.
∫ du/√(a^2-u^2) = arcsin(u/a)+C
right? So, just note that
8+2x-x^2 = 9-(x-1)^2
Now go for it.
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