Ask a New Question
Search
Asked by
Jenn
Does the series (cos(k/3))^2/2^(k/3)+1 from k=1 to infinity converge?
Answers
Answers
Answered by
Steve
since cos(u) < 1,
your terms are less than 1/(2^(k/3)+1)
sum 1/2^(k/3) converges, and your terms are less than 1/2^(k+3), your series converges
Related Questions
Related
The series 2(3a-1) + 2(3a-1)^2 + 2(3a-1)^3...Is given for wich values of a will the series converges...
16. You have a series of four chemical reactions (1--> 2 --> 3 --> 4). How do you calculate the H2 i...
ok here we go ... its a series-parellel circuit with 5 resistors. 12 volt battery- wire goes up the...
Is the series 72, 48, 32,... an arithmetic or geometric series. WHat is common difference or ratio
Does the series 1/4 - 1/2 +1 - 2 + converge or diverge. If it converges find the sum
1.What are top 10 best series? 2.what are 2023 best series?
. Look at this series: 544, 509, 474, 439, . . . What number should come next
Look at this series: 72, 76, 73, 77, 74, __, 75,... What number should fill the blank?
Given the series 1+2+3+4+5+....+n Show that Sn=n(n+1) /2
Which of the following series of temperature measurements demonstrates a clear pattern?(1 point) Re...