a boulder is thrown launched into the air with an upward velocity of 184 ft per second. Its height h in feet after t seconds is given by the function h(t)=-16t^2 +184t+6. How long does it take the boulder to reach its maximum height? What is the boulder maximum height?

Question

a boulder is thrown launched into  the air with an upward velocity of 184 ft per second. Its height h in feet after t seconds is given by the function h(t)=-16t^2 +184t+6. How long does it take the boulder to reach its maximum height? What is the boulder maximum height? 
a- 11.6 ft 5.75 seconds 
b- 549 ft 11.5 seconds 
c- 549 ft 5.75 seconds 
d- 23.2 ft 11.6 seconds

bobpursley · Answer

We just did this. h(t)=8(23-2t^1)t + 6 so at t=0, and t=11.5, h(t)=6, so max occures half way at t=11.5/2 seconds... hmax=-16(11.5/2)^2+184(11.5/2)+6 looks like b is the closest...

Steve · Answer

thank you