Asked by George
Is this formula continous on the interval (-1,1)
h(theta)=(theta)sin(theta)
I say no, but could some one explain the process involved in determining this.
h(theta)=(theta)sin(theta)
I say no, but could some one explain the process involved in determining this.
Answers
Answered by
bobpursley
How did you get no? Have you graphed it?
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