y = x (-.04 x + 8.3)
when is y = 0
at the start of course but also when
.04 x = 8.3
or x = 207.5 meters
I think you left a significant figure out :)
A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation-
y= -0.04x^2+8.3x,where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters of the rocket above ground. How far horizontally from its starting point will the rocket land?
a- 208.02m
b- 416.03m
c- 0.52m
d- 208.19m
This 68 year old grandfather is lost on this one.
3 answers
your right sorry
y=-0.04x^2+8.3x+4.3
y=-0.04x^2+8.3x+4.3
.04 x^2 - 8.3 x - 4.3 = 0
http://www.webgraphing.com/quadraticequation_quadraticformula.jsp#
http://www.webgraphing.com/quadraticequation_quadraticformula.jsp#