To graph an equation, pick a value for one variable (x) and calculate the value of y for that value of x. This gives you the coordinates for one point.
Do the same for other values of x. After you have an adequate number of coordinates, play "connect the dots."
I hope this helps. Thanks for asking.
Given 3x-2y=6, how do i find the area of triangle OPQ? I know I have to graph the equation first but I don't even know how to find the points?
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I assume - although you haven't said so - that P and Q are the points at which the line you've given cuts the X and Y axes respectively. If so, then P is the point (2,0) and Q is (0,-3). (To get those, just put Y=0 and solve your equation for X, then put X=0 and solve it for Y.) You've now got the three vertices of your triangle, and you want to calculate the area of it. But this is a right-angled triangle (look at the graph), and you already know the width and the height of it. So the area is just half the width times the hight.
1 answer