#1 should be A, look at your last sum
(1/2)[ ..0 + 9 ] = [ ....9/2]
#2
you have a 1 by 3 matrix multiply by a 3 by 1
which will give you [(6+6+0)] = [12]
1.) Find 1/2([5 -2 4 0]+[14 6 -18 9])
A. [19/2 2 -7 9/2]
B. [-9/2 -4 -11 9/2]
C. [ 19/2 2 -7 9]
D. [19 4 -14 9]
My answer: C.
2.) Is it possible to find AB when you are give A= [3 2 1] and B= [2 3 0]? (this 2, 3, 0 is suppose to line up like up and down.)
A. [12]
B. [6 6 0]
C. [6
6
0]
D. [0]
E. Not possible
My answer: E.
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