for substitution, I would, um, substitute. The 1st equation tells you that
y = -2x
So, substitute that into the 2nd equation to get
x-3(-2x) = -7
x+6x = -7
7x = -7
x = -1
Now you can find y.
As for elimination,
3x + 4y = 1
5x – 3y = 21
to eliminate y, multiply the 1st by 3 and the 2nd by 4 to get
9x+12y = 3
20x-12y = 84
now add them up and you have
29x = 87
x = 3
Now you can find y.
Show how you would solve by Substitution:
2x + y = 0
x – 3y = -7
Show how you would solve by Elimination: 3x + 4y = 1
5x – 3y = 21
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