Asked by nona
6. A 2.50 L flask was used to collect a 5.65 g sample of propane gas, C3H8. After the sample was collected, the gas pressure was found to be 956 mmHg. What was the temperature of the propane in the flask?
Answers
Answered by
MathMate
Assuming the flask was filled with propane only, and propane approximately closely an ideal gas at the given temperature, you can use the ideal gas equation
PV=nRT
where
R=8.314 J-K<sup>-1</sup>mol<sup>-1</sup>
P=pressure in pa
V=volume in m³
n=number of mols (pure number)
T=temperature in °K
Hints for conversion
1 m³ = 1000 L
mol = mass / molar mass
1 mmHg = 133.32 pa
°C = °K + 273.15
PV=nRT
where
R=8.314 J-K<sup>-1</sup>mol<sup>-1</sup>
P=pressure in pa
V=volume in m³
n=number of mols (pure number)
T=temperature in °K
Hints for conversion
1 m³ = 1000 L
mol = mass / molar mass
1 mmHg = 133.32 pa
°C = °K + 273.15
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.