Question
6. A 2.50 L flask was used to collect a 5.65 g sample of propane gas, C3H8. After the sample was collected, the gas pressure was found to be 956 mmHg. What was the temperature of the propane in the flask?
Answers
MathMate
Assuming the flask was filled with propane only, and propane approximately closely an ideal gas at the given temperature, you can use the ideal gas equation
PV=nRT
where
R=8.314 J-K<sup>-1</sup>mol<sup>-1</sup>
P=pressure in pa
V=volume in m³
n=number of mols (pure number)
T=temperature in °K
Hints for conversion
1 m³ = 1000 L
mol = mass / molar mass
1 mmHg = 133.32 pa
°C = °K + 273.15
PV=nRT
where
R=8.314 J-K<sup>-1</sup>mol<sup>-1</sup>
P=pressure in pa
V=volume in m³
n=number of mols (pure number)
T=temperature in °K
Hints for conversion
1 m³ = 1000 L
mol = mass / molar mass
1 mmHg = 133.32 pa
°C = °K + 273.15