If I have pH of lemon juice that is 2.3 after I dilute it with 9 cups of water, what is the pH and how do I figure it out?

Answer 1

Convert pH 2.3 to (H^+) with pH = -log(H^+)

Then convert 9 cups H2O to mL and I'll call that ?mL

Then (H^+) x (volume original lemon juice/? mL in 9 cups) = ? = (new H^+ in mols/L. Convert that back to pH.