Asked by Jackie
Problem 1.) Three friends want to share a circular 16-inch pizza equally by exactly only two parallel cuts. How far from the center must the cuts be? Hint: The pizza is a circle of radius 8 inches.
Problem 2.) You are at the southernmost point of a circular lake of radius 8 miles. Your plan is to swim a straight course to another point on the shore of the lake, then jog to the northernmost point. You can jog 150% as fast as you can swim. With a detailed explanation of your steps, find, in minutes, the least and the most time this trip will take if you swim at 3.5 miles per hour.
Problem 2.) You are at the southernmost point of a circular lake of radius 8 miles. Your plan is to swim a straight course to another point on the shore of the lake, then jog to the northernmost point. You can jog 150% as fast as you can swim. With a detailed explanation of your steps, find, in minutes, the least and the most time this trip will take if you swim at 3.5 miles per hour.
Answers
Answered by
Steve
since the area of a circular segment is
a = 1/2 r^2 (θ-sinθ)
you need θ such that cos(θ/2) = x/8
so, you need to solve
1/2 * 64 (2*arccos(x/8)-sin(2*arccos(x/8))) = 64π/3
x = 2.12 inches
----------------------------------
3.5 mi/hr = 0.058 mi/min
If the swim subtends an angle θ, then the distance swum is 2x, then
x/8 = sin θ/2
x = 8 sinθ/2
the distance jogged is then 8π - 8θ
total time is then
(16 sin(θ/2))/.0583 + (8π - 8θ)/.0875
If you poke around at the graph, you can prolly figure the max/min for the domain 0 <= θ <= π
http://www.wolframalpha.com/input/?i=%2816+sin%28%CE%B8%2F2%29%29%2F.0583+%2B+%288%CF%80+-+8%CE%B8%29%2F.0875
a = 1/2 r^2 (θ-sinθ)
you need θ such that cos(θ/2) = x/8
so, you need to solve
1/2 * 64 (2*arccos(x/8)-sin(2*arccos(x/8))) = 64π/3
x = 2.12 inches
----------------------------------
3.5 mi/hr = 0.058 mi/min
If the swim subtends an angle θ, then the distance swum is 2x, then
x/8 = sin θ/2
x = 8 sinθ/2
the distance jogged is then 8π - 8θ
total time is then
(16 sin(θ/2))/.0583 + (8π - 8θ)/.0875
If you poke around at the graph, you can prolly figure the max/min for the domain 0 <= θ <= π
http://www.wolframalpha.com/input/?i=%2816+sin%28%CE%B8%2F2%29%29%2F.0583+%2B+%288%CF%80+-+8%CE%B8%29%2F.0875
Answered by
Usama
LOL ITS 33,3
There are no AI answers yet. The ability to request AI answers is coming soon!