Asked by Helena
On July 16, 1882, a massive thunderstorm of Dubuque, Iowa, produced huge hailstones. The diameter of some of the hailstones was 17 inches. Ice weighs about 0.033 pounds/inches cubed. What was the approximate weight of these hailstones to the nearest pound?
Answers
Answered by
Ms. Sue
Find the volume of the hailstone.
Sphere
Solve for volume
V=4
3πr3
Multiply the volume by 0.033
Sphere
Solve for volume
V=4
3πr3
Multiply the volume by 0.033
Answered by
Yell
V=pi/6 D^3
=pi/6 (17)^3
=2572.44in^3 multiply by 0.033
=84.89lb
=pi/6 (17)^3
=2572.44in^3 multiply by 0.033
=84.89lb
Answered by
Reiny
r = 17/2 = 8.5
V = (4/3)π r^3
= (4/3)π(8.5)^3 = appr 2575.44 inches^3
mass = 2575.44(.033) = 84.89 pounds
seems very unreasonable.
A hailstone with a diameter of 17 inches ? ABsurd
V = (4/3)π r^3
= (4/3)π(8.5)^3 = appr 2575.44 inches^3
mass = 2575.44(.033) = 84.89 pounds
seems very unreasonable.
A hailstone with a diameter of 17 inches ? ABsurd
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