Question
A bomber in level flight, flying at 92m/s, releases a bomb at a height of 1950m.
(a) How long is it before the bomb strikes earth? (19.9s)
(b) How far does it travel horizontally? (1832m)
(c) What are the horizontal and vertical components of its velocity when it strikes? (195m/s)
(d) What is its velocity of impact? (216m/s)
i understand a and b , i just need help with c and d.
can u show all ur steps please, thank you!
(a) How long is it before the bomb strikes earth? (19.9s)
(b) How far does it travel horizontally? (1832m)
(c) What are the horizontal and vertical components of its velocity when it strikes? (195m/s)
(d) What is its velocity of impact? (216m/s)
i understand a and b , i just need help with c and d.
can u show all ur steps please, thank you!
Answers
horizontal is constant at 92 m/s
vertical is 9.8*19.9
so, (d) is just the resultant speed s, where s^2 = h^2 + v^2
vertical is 9.8*19.9
so, (d) is just the resultant speed s, where s^2 = h^2 + v^2
Related Questions
A bomber flying horizontally at 250 m/s releases a bomb 1500m above the ground. At the point of impa...
A bomber is flying horizontally over level terrain at a speed of 250 m/s relative to the ground and...
A bomber, flying upwards at an angle 53 with verticql releases a bomb at 800m altitude. The bomb str...
A level fight bomber flying at 300 ft/s releases a bomb at an elevation of 6400 ft. Approximately ho...