Asked by Tom
Write the equation of the line tangent to the curve
x^2 − 4y^2 + 192 = 0 at (8, 8)
Thank You
x^2 − 4y^2 + 192 = 0 at (8, 8)
Thank You
Answers
Answered by
Steve
x^2 - 4y^2 + 1292 = 0
2x - 8yy' = 0
y' = x/4y
You have x and y, so y' = 1/4
the line is thus
y-8 = 1/4 (x-8)
see at
http://www.wolframalpha.com/input/?i=plot+x%5E2+%E2%88%92+4y%5E2+%2B+192+%3D+0%2C+y+%3D+1%2F4+%28x-8%29%2B8
2x - 8yy' = 0
y' = x/4y
You have x and y, so y' = 1/4
the line is thus
y-8 = 1/4 (x-8)
see at
http://www.wolframalpha.com/input/?i=plot+x%5E2+%E2%88%92+4y%5E2+%2B+192+%3D+0%2C+y+%3D+1%2F4+%28x-8%29%2B8
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