Asked by saloni garg
probability of having all are even or odd while throwing three dices
Answers
Answered by
PsyDAG
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
Since 3 sides are even and 3 are odd, the chances of even = 3/6 = 1/2.
For three dice, probability of all even = (1/2)^3 = 1/2 * 1/2 * 1/2 = ?
Same is true for odd.
Since 3 sides are even and 3 are odd, the chances of even = 3/6 = 1/2.
For three dice, probability of all even = (1/2)^3 = 1/2 * 1/2 * 1/2 = ?
Same is true for odd.
Answered by
Steve
<u>dice</u> is already plural. No such word as dices.
well, the chance of any one die's being even or odd is 1/2
So, the chance of all three being even or all odd is (1/2)^3, since the events are independent.
well, the chance of any one die's being even or odd is 1/2
So, the chance of all three being even or all odd is (1/2)^3, since the events are independent.
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