1. Rule: a^x * a^y = a^(x+y)
b^(1/6)^3 * b^(1/6)
= b^(1/2) * b^(1/6)
= b^(1/2 + 1/6) = b^(2/3)
2.
(2x^-3)^2 (0.2x)^2
= 4x^-6 * .04x^2
= .01 x^-4
3.
(3^7)^2 (3^-4)^3
= 3^14 * 3^-12
= 3^2 = 9
Simplify each expression.
1.) (b^ 1/6)^3 b^1/6
2.) (2x^-3)^2 (0.2x)^2
3.) (3^7)^2 (3^-4)^3
1 answer