Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to your Z scores.
The Economic Policy Institute periodically issues reports on wages of entry-level workers. The institute reported that entry-level wages for male college graduates were $21.68 per hour and for female college graduates were $18.80 per hour in 2011 (Economic Policy Institute website, March 30, 2012). Assume the standard deviation for male graduates is $2.30, and for female graduates it is $2.05.
a. What is the probability that a sample of 50 male graduates will provide a sample mean within $.50 of the population mean, $21.68?
b. What is the probability that a sample of 50 female graduates will provide a sample mean within $.50 of the population mean, $18.80?
c. In which of the preceding two cases, part (a) or part (b), do we have a higher probability of obtaining a sample estimate within $.50 of the population mean?
Do we have a higher probability of obtaining a sample estimate within $.50 of the population mean?
d. What is the probability that a sample of 120 female graduates will provide a sample mean more than $.30 below the population mean?
3 answers
I need in answers of the questions pls
B.2.05/square root of (50)=.2899
.5/.2899=1.724732667
Under the z score table lookup +/- 1.72
=.9573-.0427
=.9146
.5/.2899=1.724732667
Under the z score table lookup +/- 1.72
=.9573-.0427
=.9146